April 24, 2011

Python Code to Get IP Address From Interface Name

From my previous code on How To Print Active Network Interface List in Linux using Python, I got this question.

Question from jimchris:
Nice work, now how do we get ip address from ifacedata?

My Answer:
Here's how... Add this function to your python code:
def getifip(ifn):
    import socketfcntlstruct
    sck socket.socket(socket.AF_INETsocket.SOCK_DGRAM)
    return socket.inet_ntoa(fcntl.ioctl(sck.fileno(),0x8915,struct.pack('256s'ifn[:15]))[20:24])

Then use it in your previous code like this:
print getifip(ifacedata[0])

Update: you can also download the python source code here

Wish you luck and Happy Coding!

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Umarzuki said...

with these:


# read the file /proc/net/dev
f = open('/proc/net/dev','r')

# put the content to list
ifacelist = f.read().split('\n')

# close the file

# remove 2 lines header

# loop to check each line
for line in ifacelist:

ifacedata = line.replace(' ','').split(':')

# check the data have 2 elements
if len(ifacedata) == 2:

# check the interface is up (Transmit/Receive data)
if int(ifacedata[1]) > 0:

# print the interface
print ifacedata[0]

def getifip(ifn):
import socket, fcntl, struct
sck = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
return socket.inet_ntoa(fcntl.ioctl(sck.fileno(),0x8915,struct.pack('256s', ifn[:15]))[20:24])

print getifip(ifacedata[0])

i got these:

Traceback (most recent call last):
File "iface.py", line 36, in
print getifip(ifacedata[0])
File "iface.py", line 34, in getifip
return socket.inet_ntoa(fcntl.ioctl(sck.fileno(),0x8915,struct.pack('256s', ifn[:15]))[20:24])

ApOgEE said...

I couldn't see your code properly since python rely on code indentation too and this comment area won't allow <pre> tags.

Please download my sample source code (updated on the post) and see the diff. It works fine on my PC.